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Question:

dhpattillo
dhpattillo

Put in algebraic equation: The difference of 3 times a number y and 2 equals 19.

 

I can't figure this out to help my daughter. Thanks

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Posted by dhpattillo on Tuesday January 27, 2009 at 5:38 PM and tagged with algebra, algebraic equations, math.

Answers:


  1. lynn30k Teacher
    High School - 10th Grade

    eNotes Editor

    3y-19=2

    It is worded a little strangely, but what they are saying is that 3 times the unknown number is 19 more than 2.

    Add 19 to each side of the equation; you then have 3y=21.

    Divide each side by 3, and y=7

    You could also look at it as 3y-2=19; add 2 to each side, and once again you have 3y=21

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    Posted by lynn30k on Tuesday January 27, 2009 at 6:18 PM


  2. ladyvols1 Teacher
    High School - 9th Grade

    eNotes Editor

    The concept of three times a number y and two equals 19 is simply written as

    3y+2 = 19

    To find the solution to this equasion you simply subtract 2 from each side which leaves you with 3y=17 .  At this juncture you divide each side by 3 and that gives you Y=17/3

    The soultion would be  Y= 5 2/3

    Sources:
    http://www.enotes.com/sat-prep/introduction-algebra
    http://www.enotes.com/sat-prep/question-type-6-simplifyin...

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    Posted by ladyvols1 on Tuesday January 27, 2009 at 6:25 PM

  3. burnzie77
    burnzie77 Student
    High School - 11th Grade

    3y-2=19

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    Posted by burnzie77 on Tuesday January 27, 2009 at 6:28 PM


  4. hsato

    eNotes Editor

    3y-2=19

    3y-2+2=19+2

    3y=21

    3y/3=21/3

    y=7

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    Posted by hsato on Wednesday January 28, 2009 at 10:52 AM

  5. neon-ice-cream
    neon-ice-cream Student
    High School - 9th Grade

    3y+2=19

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    Posted by neon-ice-cream on Wednesday January 28, 2009 at 12:18 PM