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Question:


catlover
Student
High School - 10th Grade

How would you solve the following eqations?

For this one, you'd need to cross multiply. (the dash represents the fraction bar)

1.     x-2/x+6 = x/2                  

2.    2x squared - 6x+3/x-1

 

Please help! Thanks!

 

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Posted by catlover on Sunday May 24, 2009 at 11:07 AM and tagged with algebra, math.

Answers:

  1. neela
    neela Teacher
    Graduate School

    eNotes Editor

    1)

    x-2/x+6 =x/2 . x and 2 are in denominators in this equation. The LCM(lowest common multiplier ) of x  and 2 is 2x. Mutiply bith sides by 2x.

    2x^2-4+12x = x^2 . Collect  similar erms together in decreasing order of dgree.. Then,

    2x^2-x^2+12x-4 =0 ==>

    (x^2+12x)-4 = 0

    ((x+6)^2 -36)-4 =0 .==>

    (x+6)^2  -40 =0  ==>

    (x+6)^2  = 40

    x+6  = + or -  sqrt(40) =  +or- 2sqrt(10)

    x  = -6+2sqrt(10)  or  x = -6-2sqrt(10) .

     

    2)

    2x^2-6x/x-1 .  This is an expression only but not an equation.

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    Posted by neela on Thursday August 20, 2009 at 7:21 AM