Math Group
Question:
Find the second grade function if f(-1)=1, f(0)=1 , f(1)=3.
Answers:
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eNotes Editor
Posted by giorgiana1976 on Thursday April 2, 2009 at 8:17 AMBest answer as selected by question asker.
The second grade function is described by the expression:
f(x)=ax^2 + bx + c
f(-1)=1
f(-1)=a*(-1)^2 + b*(-1) + c=a-b+c
a-b+c=1
f(0)=1
f(0)=a*(0)^2 + b*(0) + c=c
c=1
f(1)=3
f(1)=a*(1)^2 + b*(1) + c=a+b+c
a+b+c=3, but c=1
a+b+1=3
a+b=2
We have also the expression a-b+c=1 and c=1
a-b+1=1
a-b=0
a=b, but a+b=2=>a+a=2
2a=2
a=1
b=1
c=1

