Math Group
Question:
Find the multiple roots of the polynomial, if there are any:
(n-1)X^n - n*X^(n-1)+1
Answers:
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eNotes Editor
Posted by neela on Tuesday May 26, 2009 at 1:57 AMLet f(x) = (n-1)x^n - n*x^(n-1)+1
If f(x) has r mutiple roots , then f '(x) has same r-1 mutiple roots.
f'(x) = d/dx{(n-1)x^n -nx^(n-1) +1 }
=n(n-1)x^(n-1) -n(n-1)x^(n-2)
=n(n-n)x^(n-2){x-1}, Thus x =0 or x-1=0 or x=1 are the roots of f'(x).
But x= 0 is not a root of f(x) , as f(0) =
=( n-1)*0-n*0*+1 =1 and not =0.
When x-1 =0 or x=1 , f(1) =(n-1)*1-(n)*1+1 =0. Therefore, x=1 is a mutiple root of f(x) order of multiplicity is 2 i.e one higher than that of f'(x).
