Math Group
Question:
Calculate the value of the ratio below:
(1234567890)/[(1234567891)^2-(1234567890*1234567892)]
Answers:
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eNotes Editor
Posted by neela on Monday September 28, 2009 at 4:30 AMLet 1234567891=x. So,
124567890=x-1 and
1234567892=x+1 .
Therefore, the given expression is (x-1)/{(x)]^2-(x-1)*(x+1)}
=(x-1)/{x^2 -(x-1)(x+1)}
=(x-1)/(x^2 - (x^2-1)
=(x-1)(x^2-x^2+1}
=(x-1)/( 1}
=x-1
=1234567890, as x=1234567891 we assumed.
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eNotes Editor
Posted by krishna-agrawala on Monday September 28, 2009 at 8:56 AMLet 1234567891 = x
Then: 1234567890 = x-1 and 1234567892 = x+1
Substituting these values in the given expression the expression becomes:
(x-1)/[x^2 - (x-1)*(x+1)] = (x-1)/[x^2 - (x^2-1)] = (x-1)/(x^2 - x^2 + 1)
= (x-1)/1 = x-1 = 1234567890
