Math Group
Question:
Calculate the sum 1+4+7+....+31.
Answers:
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Posted by nick12 on Saturday May 30, 2009 at 7:42 AM
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eNotes Editor
Posted by giorgiana1976 on Saturday May 30, 2009 at 9:18 AM1+(1+3)+(1+2*3)+....+(1+10*3)
=(1+1+...+1)+3*(1+2+3+...+10)=
=11+ (1+10)*30/2=11(1+15)=176
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Posted by fahad-alfahad on Sunday May 31, 2009 at 11:18 PM
sum = n/2*(a+L) {n=number of term ,a=first term ,L=last term)
sum = 10/2 * ( 1 + 31 )
sum = 5 * 32 = 160
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Posted by aj11 on Tuesday June 2, 2009 at 6:05 PM
If you see carefully, you can find that this is the sum of arithmetic sequence by the number of 3
The sum of arithmetic sequence is n/2*(a+L) {n=number of term ,a=first term ,L=last term)
Then.10/2 * ( 1 + 31 )=5 * 32 = 160



