Math Group
Question:
Calculate lim S, where S=1/(1*2) + 1/(2*3) + ...+ 1/[n*(n+1)].
Answers:
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eNotes Editor
Posted by neela on Wednesday May 27, 2009 at 8:52 PMSn = 1/(2*3)+1/(3*4)++....1/(n*(n+1))
=(1/2-1/3) +(1/3-1/4)+ (1/4-1/5)+....(1/n - 1/(n+1))
=1/2 +(1/3-1/3)+1/4-1/4)+.....(1/n-1/n)-1/(n+1)
=1/2+0+0...+0 -1/(n+1)
=1/2 + 1/(n+1)
Lim n->inf Sn = 1/2 as 1/(n+1) approaches 0 as n becomes infinite.
