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    <title>Math Group at eNotes</title>
    <link>http://www.enotes.com/math/group</link>
    <description>The latest discussion, including questions and answers, from the Math Group at eNotes.</description>
    <lastBuildDate>Wed, 11 Nov 2009 07:29:12</lastBuildDate>
    <language>en-us</language>
    <item>
        <title><![CDATA[To simplify {(3/6)+(2/3)x(1/3)}-(1/3)/(3/2)
Solution:...]]></title>
        <link>http://www.enotes.com/math/q-and-a/simplify-3-6-2-3-x-1-3-1-3-3-2-114795</link>
        <description><![CDATA[To simplify {(3/6)+(2/3)x(1/3)}-(1/3)/(3/2)
Solution:
{(3/6)+(2/3)x(1/3)}-(1/3)/(3/2)
In the innermost bracket, we have 3/6 which is equal to 1/2 and (2/3)*(1/3) is equal to 2/9.
So the given expression becomes:
={(1/2+2/9)}-(1/3)/(3/2),
=3/6+2/9-2/9 ,  as  (1/3)/(3/2) is equalto (1/3)(2/3)=2/9
=3/6
=1/2
So the given expression simplifies to the value 1/2.]]></description>
        <guid>http://www.enotes.com/math/q-and-a/simplify-3-6-2-3-x-1-3-1-3-3-2-114795</guid>
        <pubDate>Wed, 11 Nov 2009 07:29:12 PST</pubDate>
    </item>
    <item>
        <title><![CDATA[{(3/6) + (2/3)*(1/3)} - (1/3)/(3/2)
= {3/6 + (2*1)/(3*3)} - (1*2)/(3*3)...]]></title>
        <link>http://www.enotes.com/math/q-and-a/simplify-3-6-2-3-x-1-3-1-3-3-2-114795</link>
        <description><![CDATA[{(3/6) + (2/3)*(1/3)} - (1/3)/(3/2)
= {3/6 + (2*1)/(3*3)} - (1*2)/(3*3)
(Please not that in multiplication of two fractions. the numerator is multiplied by numerator and denominator is multiplied denominator. In case of one fraction is divided by another fraction then the division operation (/)can be changed to multiplication (*) by keeping the first fraction as it is and reversing the numerator and denominator of the second fraction.)
= 3/6 +...]]></description>
        <guid>http://www.enotes.com/math/q-and-a/simplify-3-6-2-3-x-1-3-1-3-3-2-114795</guid>
        <pubDate>Wed, 11 Nov 2009 07:07:35 PST</pubDate>
    </item>
    <item>
        <title><![CDATA[Simplify,{(3/6)+(2/3)x(1/3)}-(1/3)/(3/2)]]></title>
        <link>http://www.enotes.com/math/q-and-a/simplify-3-6-2-3-x-1-3-1-3-3-2-114795</link>
        <description><![CDATA[Simplify,{(3/6)+(2/3)x(1/3)}-(1/3)/(3/2)]]></description>
        <guid>http://www.enotes.com/math/q-and-a/simplify-3-6-2-3-x-1-3-1-3-3-2-114795</guid>
        <pubDate>Wed, 11 Nov 2009 06:51:34 PST</pubDate>
    </item>
    <item>
        <title><![CDATA[Mechanics question help please? Thank you very much!
]]></title>
        <link>http://www.enotes.com/math/q-and-a/mechanics-question-help-please-thank-you-very-much-114727</link>
        <description><![CDATA[Mechanics question help please? Thank you very much!
]]></description>
        <guid>http://www.enotes.com/math/q-and-a/mechanics-question-help-please-thank-you-very-much-114727</guid>
        <pubDate>Tue, 10 Nov 2009 20:05:04 PST</pubDate>
    </item>
    <item>
        <title><![CDATA[Logical Reasoning]]></title>
        <link>http://www.enotes.com/documents/logical-reasoning-47715</link>
        <description><![CDATA[]]></description>
        <guid>http://www.enotes.com/documents/logical-reasoning-47715</guid>
        <pubDate> PST</pubDate>
    </item>
    <item>
        <title><![CDATA[[-1  * [-1, 2]
3]      . The  product of these 2by1 matrix and...]]></title>
        <link>http://www.enotes.com/math/q-and-a/find-matrix-that-solve-equation-identity-matrix-2-114495</link>
        <description><![CDATA[[-1  * [-1, 2]
3]      . The  product of these 2by1 matrix and 1by2 matrix is a 2by2 matrix as below:
[1 , -2
-3 , 6] , which with a  2by2 matrix, F^T (transpose of F)  can give the product an identity matrix of the order 2by2, i.e 28 I  Therefore,
[-1 , 2
-3 , 6]* F^T = 28I , is the equation to be solved for the 2by2 matrix F.
Let F=
[a,b
c,d]. Then, F^T=F'=
[a,c
b,d]
Therefore,
[1 -2
-3, 6]*F^T =
[a-2b, c-2d
-3a+6b, -3c+6d] =28I...]]></description>
        <guid>http://www.enotes.com/math/q-and-a/find-matrix-that-solve-equation-identity-matrix-2-114495</guid>
        <pubDate>Tue, 10 Nov 2009 11:12:22 PST</pubDate>
    </item>
    <item>
        <title><![CDATA[Find the matrix that solves the equation. I is the identity matrix....]]></title>
        <link>http://www.enotes.com/math/q-and-a/find-matrix-that-solve-equation-identity-matrix-2-114495</link>
        <description><![CDATA[Find the matrix that solves the equation. I is the identity matrix.
2   1       1   2
-1  3   .  -1  2  F^T  =28I]]></description>
        <guid>http://www.enotes.com/math/q-and-a/find-matrix-that-solve-equation-identity-matrix-2-114495</guid>
        <pubDate>Tue, 10 Nov 2009 08:57:57 PST</pubDate>
    </item>
    <item>
        <title><![CDATA[We can answer by simple application of Differentiation.
For either min...]]></title>
        <link>http://www.enotes.com/math/q-and-a/whats-equation-minimum-product-when-dealing-with-113107</link>
        <description><![CDATA[We can answer by simple application of Differentiation.
For either min or max the common condition is Ist derivative zero and for max  The IInd derivatime must be negative and for min the IINd derivative must be +ve.
Let x be one number and the Iind number is x-10.
P=x(x-10) =x^2-10x
dP/dX=2x-10.
d^2P/dx^2 =2 (+ve). Therefor minimum value at dP/dx=0
2x-10=0 ie x=5.
Therefore the numbers are 5 and -5.
Min prodcuct = 58-5 =-25.]]></description>
        <guid>http://www.enotes.com/math/q-and-a/whats-equation-minimum-product-when-dealing-with-113107</guid>
        <pubDate>Tue, 10 Nov 2009 07:06:18 PST</pubDate>
    </item>
    <item>
        <title><![CDATA[Slope intercept form is x/a+y/b=1 where a ix intercept on x- axis and ...]]></title>
        <link>http://www.enotes.com/math/q-and-a/ok-dont-get-what-do-slope-intercept-y-mx-b-114265</link>
        <description><![CDATA[Slope intercept form is x/a+y/b=1 where a ix intercept on x- axis and  b is intercept on y -axis.slope m= TanA =b/a
The givem Eqis Y=2x+4 or 2x-y=-4 Divide both sides by -4 We get
x/(-2)+y/(-4)=1
Therefore a=-2 and b= -4.and slope = b/a = 2.
Since both intercepts are negative the graph lies in IIIrd the Quadrant.
 ]]></description>
        <guid>http://www.enotes.com/math/q-and-a/ok-dont-get-what-do-slope-intercept-y-mx-b-114265</guid>
        <pubDate>Tue, 10 Nov 2009 06:48:51 PST</pubDate>
    </item>
    <item>
        <title><![CDATA[x/(x-4)=5x/(x2-x-12)-3/(x+3).
To find x.
Solution:
The expression,...]]></title>
        <link>http://www.enotes.com/math/q-and-a/x-x-4-5x-x2-x-12-3-x-3-114463</link>
        <description><![CDATA[x/(x-4)=5x/(x2-x-12)-3/(x+3).
To find x.
Solution:
The expression, x^2-x-12 is a denominator on the right  is equal to (x-4)(x+3) on factorisation.
Therefore, the LCM of the denominators (x-4), (x^2-x-12) and (x+3) appearing in the given equation  is (x-4)(x-3).
Multiplying by the LCM both sides of the equation, we get:
[x/(x-4)]*(x-4)(x+3)=[ 5x/(x^2^2-x-12)]*(x-4)(x+3)-[3/(x+3)]*(x-4)(x+3), which simplifies to:
x(x+3)=5x-3(x-4)...]]></description>
        <guid>http://www.enotes.com/math/q-and-a/x-x-4-5x-x2-x-12-3-x-3-114463</guid>
        <pubDate>Tue, 10 Nov 2009 06:39:16 PST</pubDate>
    </item>
    <item>
        <title><![CDATA[I will answer with mathematical analysis:Work done(W) = Force x distance...]]></title>
        <link>http://www.enotes.com/math/q-and-a/commonly-used-unit-kilowatt-hour-physical-114177</link>
        <description><![CDATA[I will answer with mathematical analysis:Work done(W) = Force x distance (Units N-mt or Kg-mt) = = F*x
The rate of doing work is called Power.Mathematically the derivative of Work done is Power.ie dW/dt = d(F*x)/dt = F*v
Units = N-m/sec = 1 watt.THe capacity of doing work is called Emergy.hence it is time dependent. Physically Work done and energy are same.dW=P*dt
Emergy =Powerxtime =watt-sec or biger unit KWh. Therefore Answer is B.]]></description>
        <guid>http://www.enotes.com/math/q-and-a/commonly-used-unit-kilowatt-hour-physical-114177</guid>
        <pubDate>Tue, 10 Nov 2009 06:34:01 PST</pubDate>
    </item>
    <item>
        <title><![CDATA[I believe the given equation is meant to be:
x/(x - 4) = 5x/(x^2 - x -...]]></title>
        <link>http://www.enotes.com/math/q-and-a/x-x-4-5x-x2-x-12-3-x-3-114463</link>
        <description><![CDATA[I believe the given equation is meant to be:
x/(x - 4) = 5x/(x^2 - x - 12) - 3/(x + 3)
To solve this equation we multiple every term by (x + 4)*(x + 3), which is equal to (x^2 - x - 12).
Thus the equation becomes:
x*(x + 3) = 5x - 3*(x - 4)
Therefore:
x^2 + 3x = 5x -3x +12
Therefore: x^2 + x - 12 = 0
Therefore: x^2 - 3x + 4x - 12 = 0
Therefore: x*(x - 3) + 4*(x - 3) = 0
Therefore: (x - 3)*(x + 4) = 0
Therefore: (x - 3) = 0 or (x + 4) = 0...]]></description>
        <guid>http://www.enotes.com/math/q-and-a/x-x-4-5x-x2-x-12-3-x-3-114463</guid>
        <pubDate>Tue, 10 Nov 2009 05:33:33 PST</pubDate>
    </item>
    <item>
        <title><![CDATA[x/(x-4)=5x/(x2-x-12)-3/(x+3)]]></title>
        <link>http://www.enotes.com/math/q-and-a/x-x-4-5x-x2-x-12-3-x-3-114463</link>
        <description><![CDATA[x/(x-4)=5x/(x2-x-12)-3/(x+3)]]></description>
        <guid>http://www.enotes.com/math/q-and-a/x-x-4-5x-x2-x-12-3-x-3-114463</guid>
        <pubDate>Tue, 10 Nov 2009 04:59:21 PST</pubDate>
    </item>
    <item>
        <title><![CDATA[y=mx+b is the slope intercept form of a straight line.
When x=0,  y=...]]></title>
        <link>http://www.enotes.com/math/q-and-a/ok-dont-get-what-do-slope-intercept-y-mx-b-114265</link>
        <description><![CDATA[y=mx+b is the slope intercept form of a straight line.
When x=0,  y= m*0+b=b. Therefore, (0,b) which is a point on y axis  and it intercepts y axis at a distance b from the origin.
Now Let us plug y=0 in the equation, 0=m+b. So, x = -b/m. So,
In the triangle ABC, A = (-b/m,0),  O, the origin =(0,0) and C= (0,b), the slope of the line y=mx+b is given by:
slope = tan angleOAC = OC/AO= (b-0)/[0-(-b/m)]= b/(b/m)=m.
Therefore, m is the slope and...]]></description>
        <guid>http://www.enotes.com/math/q-and-a/ok-dont-get-what-do-slope-intercept-y-mx-b-114265</guid>
        <pubDate>Mon, 9 Nov 2009 16:52:41 PST</pubDate>
    </item>
    <item>
        <title><![CDATA[Logical Reasoning 2]]></title>
        <link>http://www.enotes.com/documents/logical-reasoning-2-47713</link>
        <description><![CDATA[]]></description>
        <guid>http://www.enotes.com/documents/logical-reasoning-2-47713</guid>
        <pubDate> PST</pubDate>
    </item>
    <item>
        <title><![CDATA[Logical Reasoning 1]]></title>
        <link>http://www.enotes.com/documents/logical-reasoning-1-47711</link>
        <description><![CDATA[]]></description>
        <guid>http://www.enotes.com/documents/logical-reasoning-1-47711</guid>
        <pubDate> PST</pubDate>
    </item>
    <item>
        <title><![CDATA[Y is equal to mx+b, with m being the slope and b being the spot on the Y...]]></title>
        <link>http://www.enotes.com/math/q-and-a/ok-dont-get-what-do-slope-intercept-y-mx-b-114265</link>
        <description><![CDATA[Y is equal to mx+b, with m being the slope and b being the spot on the Y axis that the line intercepts at. So, for Y=2x+4, it would have a slope of 2/1, the line would intercept at 4, and it would go to the right. Does that help?]]></description>
        <guid>http://www.enotes.com/math/q-and-a/ok-dont-get-what-do-slope-intercept-y-mx-b-114265</guid>
        <pubDate>Mon, 9 Nov 2009 13:50:50 PST</pubDate>
    </item>
    <item>
        <title><![CDATA[ok I dont get what to do for slope intercept Y=mx+b]]></title>
        <link>http://www.enotes.com/math/q-and-a/ok-dont-get-what-do-slope-intercept-y-mx-b-114265</link>
        <description><![CDATA[ok I dont get what to do for slope intercept Y=mx+b]]></description>
        <guid>http://www.enotes.com/math/q-and-a/ok-dont-get-what-do-slope-intercept-y-mx-b-114265</guid>
        <pubDate>Mon, 9 Nov 2009 13:24:51 PST</pubDate>
    </item>
    <item>
        <title><![CDATA[X=1 because 2x1+3=5
1+4=5
 ]]></title>
        <link>http://www.enotes.com/math/q-and-a/x-4-2x-3-113039</link>
        <description><![CDATA[X=1 because 2x1+3=5
1+4=5
 ]]></description>
        <guid>http://www.enotes.com/math/q-and-a/x-4-2x-3-113039</guid>
        <pubDate>Mon, 9 Nov 2009 11:13:26 PST</pubDate>
    </item>
    <item>
        <title><![CDATA[a.The work the flight attendant does on the flight bag =  component of...]]></title>
        <link>http://www.enotes.com/math/q-and-a/attendant-pulls-her-74-2n-flight-bag-distance-324m-114203</link>
        <description><![CDATA[a.The work the flight attendant does on the flight bag =  component of force she pulls the bag along the floor * the displacement of the bag = (37.9N cos 55.2 degree)*(324 meter) = 7008.1343 J
b. The force of friction is equal but opposite to the component of the exerted force resolved along the floor in the direction of displacement * displacement =  (- 37*9N cos 55.2)*(324) cos (angle between frictional force and direction of...]]></description>
        <guid>http://www.enotes.com/math/q-and-a/attendant-pulls-her-74-2n-flight-bag-distance-324m-114203</guid>
        <pubDate>Mon, 9 Nov 2009 09:55:18 PST</pubDate>
    </item>
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