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I do know something about the golden segment but I cannot construct it. I've tried to follow some tips but it was in vain. Posted by sonnia on Mar 20, 2009. |
Math Group
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Steps for drawing the golden segment: 1. Draw a line L. 2. Choose a point A on the line L. In this point, we'll draw a perpendicular M. 3. We consider one segment [AB], with the length 1, on the line M. (the length 1 is a reference length). 4. We consider one segment [AC], with the length 1, on the line L. 5. We consider one segment [CD], with the length 1, on the line M, so as AD=2. 6. We'll measure in compasses the length BD, and from the point B, with the distance kept in compasses, we'll intersect the line M in the point E. The ratio AE/AD is the gold ratio. Posted by giorgiana1976 on Mar 20, 2009. |
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Construct a right angled triangle with AB =2 units and the hypotenuse 3 units: (On a line AB =2 units errect a perpendicular AY at B.With compass measuring 3 units ,with A as centre draw the arc to cut AY at C. That gives the right angled triangle ABC) In the right angled triangle ABC, BC = sqrt(3^2-2^2)= sqrt5. Now mark off on the line AB extended with compass measuring equal to BC with B as centre such that BD= BC. Draw a perpendicular bisector to AB to find the mid point of AB at say E. Now BE equal to one unit. Now ED = EB+BD =1+sqrt5 units. AB =2units Therefore, ED/AB= (1+sqrt5)/2. That is the golden ratio with proof and with geometrical construction ascertaining the visuality of this irrational ratio, but still being called golden ratio. Posted by neela on Jun 10, 2009. |

