eNotes Homework Help is a way for educators to help students understand their school work. Our experts are here to answer your toughest academic questions! Once it’s posted to our site, your question could help thousands of other students.
Popular Titles
Showing
in

MathYou need to find value for which sin equals `sqrt2/2 ` . Using a unit circle, it can be determined that the answer is `pi/4 `

MathYou need to find value for which sin equals `sqrt3/2 ` . Using a unit circle, it can be determined that the answer is `pi/3 `

MathYou need to find value for which tan equals `sqrt3/3 ` . Using a unit circle, it can be determined that the answer is `pi/6 `

MathGraph: It approaches zero, but it never gets there (limit does not exist).

MathGraph, It looks like y is 0 when x approaches 0.

MathIt is even. `cosx=cos(0x) ` `cos(0x)=sin0sinx+cos0cosx=cosx ` Therefore, `cos ` is even `sec(x)=1/cosx ` This equals `1/cosx=secx ` Therefore, `sec ` is even

MathGraph

MathGraph

MathGraph

MathGraph

MathGraph

MathGraph

MathGraph

MathGraph

MathGraph

MathGraph

MathGraph

MathGraph

MathGraph

MathGraph

MathGraph

MathGraph

MathGraph

MathGraph

MathGraph

MathGraph

MathGraph

MathGraph

MathGraph

MathGraph

MathGraph

MathGraph

MathGraph

MathGraph

MathGraph

MathGraph

MathGraph

MathGraph

MathGraph

MathBring up the exponent, `log_(3)(5x)^(1/4) `

MathBring up the exponent, `log_(6)(2x)^(4) `

MathBring up the exponent, `logxlog(x+1)^2 ` Condense by division `log(x/(x+1)^2) `

MathBring up the exponents in both terms `ln8^2+ln(z4)^5 ` ` ` Condense by multiplication `ln(8^2)(z4)^2 ` Simplify, `ln64(z4)^2 `

MathBring up the exponents `logxlogy^2+logz^3 ` ` ` `log(x/y^2)+logz^3 ` `log((xz^3)/y^2) `

MathBring up the exponents `log_3x^3+log_3y^4log_3z^4` ` ` Condense using multiplication and division `log_3(x^3*y^4)log_3z^4 ` `log_(3)((x^3y^4)/(z^4)) `

MathCondense using multiplication and division `lnxln((x+1)/(x1)) ` `ln(x/((x+1)/(x1))) ` Simplify, `ln((x(x1))/(x+1)) `

Math`4lnz(z+5)ln(z5)^2` `ln(z(z+5))^4ln(z5)^2 ` `ln(((z(z+5)^4))/(z5)^2) `

Math`(1/3)(ln(x+3)^2+lnxln(x^21)) ` `(1/3)(ln(((x+3)^2)x)/(x^21)) ` `ln(((x+3)^2x)/(x^21))^(1/3) `

Math`2(lnx^3ln(x+1)ln(x1))` `2(lnx^3ln((x+1)/(x1)))` `2(ln(x^3)/((x+1)/(x1))) ` `ln((x^(3)*(x1))/(x+1))^2 `

MathYou need to find the absolute extrema of the function, hence, you need to differentiate the function with respect to x, such that: `f'(x) = (2x^3  6x)'` `f'(x) = 6x^2  6` You need to solve for x...