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z to the 5th power - 4z to the 4th power - 21 z to the third power factor completely
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High School Teacher
Take out the first common factor of `z^3`
`therefore =z^3(z^2-4z-21) `
Now we can factorize the remaining bracket by using the factors of the 1st term (`z times z)` and those of the 3rd term that will render a middle term of -4 (that is, `7 times 3)`
`therefore = z^3(z+3)(z-7)`
Posted by durbanville on May 23, 2013 at 8:08 PM (Answer #1)
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