You are shopping at the fruit market.You want to spend no more than $12.00 on apples and bananas.Bananas cost $2 per bunch,and apples cost $4 per bag

question:

A.please write the inequality.

B.find 3 possible combinations of bananas and apples that you can buy.write each combination as an ordered pair.let x be the number of banana bunches,and let y be the number of apple bags.

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The inequality is:

2x + 4y </= 12 [that should be < on top of _ , for less than or equal to, but I can't type that here]

so, x is the number of bunches of bananas (at $2 each) and y is the number of bags of apples (at $4 each). Since you can't spend more than $12, the purchase must be *less than or equal to* 12.

Three possible combinations would be:

x = 1 and y = 2 (2*1 + 4*2 = 2 + 8 = 10)

x = 2 and y = 2 (2*2 + 4*2 = 4 + 8 = 12)

x = 3 and y = 1 (2*3 + 4*1 = 6 + 4 = 10)

A. 2x + 4y < 12 or y < -1/2x + 3

remember x = bananas and y = apples

**Note all the < are < and = to.

The inequality is:

2x+4y less than or equal to 12 dollars

Possible scenarios:

- Buy four bananas and 1 apple = 12 dollars
- Buy two bananas and two apples= 12 dollars
- Buy 1 banana and two apples= 10 dollars

2x+4y `<=` 12 dollars

Possible combinations:

1. 4 bananas and 1 apple

2. 1 apple and 3 bananas

3. 2 apples and 2 bananas

A. So this person wants to spend no more than $12.00. The mouth of the inequality symbol will automatically point in the direction of $12.00 with a equal to or less symbol.

$12.00 >/

Now we know the cost of the bananas and apples so the equation to figure that out will go on the right so...

$12.00 >/ $2x+ $4Ay

B Three possible combinations you could buy would be...

- 2 apples and 2 oranges
- 4 oranges and 1 apple
- 1 apple and 3 oranges

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