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High School Teacher
This is differential equation with separated variables.
Now we integrate whole equation.
`int dy/(y-1)=int cotx dx`
`ln(y-1)=ln (sin x)+ln C=ln(C sin x)`
Hence your function (or set of functions to be exact) is
`y(x)=1+Csin x` where `C in RR.`
Posted by tiburtius on October 25, 2013 at 7:15 PM (Answer #1)
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