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If `y=sqrtX` , what is the value of `y^25 + 121 - y^50` ?
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(Level 1) Associate Educator, Expert
Given that `y = sqrt(x)` , we want to calculate the value of `y^25 + 121 - y^50` , in terms of `x` .``
In that case, we simply substitute the value of `y` to the expression:
Note that `y = sqrt(x) = x^(1/2)` .
`y^25 + 121 - y^50 = (x^(1/2))^25 + 121 - (x^(1/2))^50`
Using laws of exponents we get the following expression:
`x^(25/2) + 121 - x^(50/2)`
which then simplifies to:
`x^(25/2) + 121 - x^25`
`sqrt(x^25) + 121 - x^25`
`(sqrt(x))^25 + 121 - x^25`
Posted by mvcdc on July 16, 2013 at 2:00 AM (Answer #1)
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