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y=sqrt 3x +sqrt5x, dy/dx=? The square root extends over the top of the 5x square root...
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`y = sqrt3x+sqrt5x`
We know that if;
`y = sqrt(ax) ` then
`dy/dx = 1/(2sqrt(3x))xx3+1/(2sqrt(5x))xx5`
So the answer is;
Posted by jeew-m on February 26, 2013 at 3:24 AM (Answer #1)
Posted by pramodpandey on February 26, 2013 at 5:52 AM (Answer #2)
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