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(x-y)(x+y) (x^2+y^2) (x^4+y^4)

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ankesh1323 | Student, Undergraduate | eNotes Newbie

Posted May 25, 2012 at 5:49 PM via web

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(x-y)(x+y) (x^2+y^2) (x^4+y^4)

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rcmath | High School Teacher | (Level 1) Associate Educator

Posted May 25, 2012 at 6:37 PM (Answer #1)

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The trick to this problem is to know what to multiply first. 
Difference if square rule states: `(x-y)(x+y)=(x^2-y^2)`

Keeping that in mind, we will work from left to right in order to apply this rule few times without having to do a lot of work.

`(x-y)(x+y)(x^2+y^2)(x^4+y^4)=`

`(x^2-y^2)(x^2+y^2)(x^4+y^4)=`

`(x^4-y^4)(x^4+y^4)=`

`(x^8-y^8)`

 

 

 

 

 

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