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X and Y moving in same direction, at a point, X travelling with a 16ms-1 and retarding...

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naveenkolambage | Student, Undergraduate | eNoter

Posted August 15, 2011 at 1:04 PM via web

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X and Y moving in same direction, at a point, X travelling with a 16ms-1 and retarding at 6ms-2 overtakes Y travelling at 8 and acc. at 2

how to calculate the distance of y from X when velocities of X and Y are equal, using a velocity time graph.

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naveenkolambage | Student, Undergraduate | eNoter

Posted August 15, 2011 at 1:14 PM (Answer #1)

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get the y axis as ms-1 and then the velocities are equal at the intersecting point.

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santaone | High School Teacher | eNoter

Posted September 11, 2011 at 9:13 AM (Answer #2)

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vx = 16 - 6t

vy = 8 + 2t

Plot Velocity on Y axis and time on X axis

When vx = vy the two lines intersect t = 1 sec.

At that point distance travelled by x is area under line vx

= (16 + 10 ) /2

which is 8 meters.

Distance travelled by y is area under the line vy

=(8 + 10 )/2

which is 9 meters.

Therefore the distance between the two is 9-8 = 1 Meters.

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