X and Y moving in same direction, at a point, X travelling with a 16ms-1 and retarding at 6ms-2 overtakes Y travelling at 8 and acc. at 2
how to calculate the distance of y from X when velocities of X and Y are equal, using a velocity time graph.
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vx = 16 - 6t
vy = 8 + 2t
Plot Velocity on Y axis and time on X axis
When vx = vy the two lines intersect t = 1 sec.
At that point distance travelled by x is area under line vx
= (16 + 10 ) /2
which is 8 meters.
Distance travelled by y is area under the line vy
=(8 + 10 )/2
which is 9 meters.
Therefore the distance between the two is 9-8 = 1 Meters.
get the y axis as ms-1 and then the velocities are equal at the intersecting point.
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