If x^x^x^∞ = 3, then value of x is:

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You need to solve for `x` the equation `((x^x)^x)^oo = 3` using limits and the properties of exponentials, such that:

`lim_(x->oo) x^(x*x*oo) = lim_(x->oo) x^oo `

`=> lim_(x->oo) x^oo = 3 `

`x = lim_(x->oo) (3^(1/oo)) => x = 3^lim_(x->oo) (1/oo)`

`x = 3^0 => x = 1`

**Hence, evaluating x using limits and the properties of exponentials, yields **`x = 3^(1/oo) = root(oo)(3) => x = 1.`

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