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X - rays are produced in an X - ray tube by a target potential of 62.0 kV. If an...

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roshan-rox | (Level 1) Valedictorian

Posted May 6, 2013 at 1:46 PM via web

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X - rays are produced in an X - ray tube by a target potential of 62.0 kV. If an electron looses one half
of its incoming energy after one collision the minimum wavelength of the X - ray photon produced is
(hc = 1240 eVnm)


(1) 4 × 10−2 nm 

(2) 6 × 10−2 nm

(3) 8 × 10−2 nm

(4) 4 × 10−3 nm

(5) 8 × 10−3 nm

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sciencesolve | Teacher | (Level 3) Educator Emeritus

Posted May 7, 2013 at 6:02 AM (Answer #1)

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You may evaluate the shortest wavelength produced, using the following equation:

`lambda_0 = (hc)/(e*V)`

The problem provides `hc = 1240 eVnm` and the energy of `(1/2)*62KV = 31 KV` , such that:

`lambda_0 = (1240)/(31*10^3)`

`lambda_0 = 40*10^(-3) => lambda_0 = 4*10*10^(-3) => lambda_0 = 4*10^(1-3) => lambda_0 = 4*10^(-2) nm`

Hence, evaluating the shortest wavelength produced, yields `lambda_0 = 4*10^(-2)` nm, hence, you need to select the first answer.

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