**If x^3x =**** 3x****^4x,**** then find x.**

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You should move the terms to one side such that:

`x^(3x)- 3x^(4x) = 0`

You need to factor out `x^(3x) ` such that:

`x^(3x)(1 - 3x^(4x-3x)) = 0 => x^(3x)(1 - 3x^x) = 0 `

Since `x^(3x)!=0` , then only `1 - 3x^x = 0 => 3x^x = 1`

You need to divide by 3 both sides such that:

`x^x = 1/3`

You need to sketch the graphs of the function `y=x^x` and the graph of the function `y=1/3` such that:

**Notice that the graphs do not intersect, hence, the given equation has no solution.**

x^3x = 3x^4x

Divide both sides by x^3x

0 = (3x^4x) / (x^3x)

According to laws of exponents, when dividing powers, the exponents are subtracted.

(x^4x) / (x^3x) = x^(4x-3x) = x^x

Now we have the equation

0 = 3x^x

Divide both sides by 3.

0 = x^x

In order for a power to equal 0, the base would have to be 0 and the exponent would have to be a positive number. Since both the base and the exponent are x (and therefore the same number), this is impossible.

There is no solution.

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