(x + 3)(x − 1) = − x + 1 Solve for x.
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`(x+3)(x-1) = -x+1`
`(x+3)(x-1) = -(x-1)`
See that (x-1) term in both sides cancel out.
`(x+3) = -1`
`x = -1-3`
`x = -4`
So the answer is x = -4.
It is quadratc equation so it has two roots
Also we can verify it wth help of graph
f(x)=(x+3)(x-1)+(x-1) The zeros of f(x) is root of equation f(x)=0
f(x) eets x-axis at x=-4 and x=1
we expand the brackets
x=-4 or 1
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