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[x^2 + x + 1] = x+1 Solve the equation.
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If X^2 + X + 1 = X+1, you'd do the following:
Subtract 1 from each side. That leaves this: X^2 + X = X
Then, subtract X from each side. That leaves this: X^2 = 0
Solve for X by taking the square root; that leaves X= 0
Posted by gbeatty on February 26, 2009 at 3:55 AM (Answer #1)
Best answer as selected by question asker.
We'll apply the definition of the whole part, which is
We note that
[x^2 + x + 1] belongs to Z
But x^2 + x + 1=x+1 => x+1 belongs to Z => x belongs to Z
By applying the definition of whole part:
[x^2 + x + 1]<x^2 + x + 1<[x^2 + x + 1]+1
But [x^2 + x + 1]=x+1
x+1<x^2 + x + 1<x+1+1
x^2 belongs to [0,1) crossed with Z set, so x=0
Posted by giorgiana1976 on February 26, 2009 at 5:09 AM (Answer #2)
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