If `x^2 - a = 14` and `x^2+a=16,` what is the value of `a` ?



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justaguide's profile pic

Posted on (Answer #1)

It is given that x^2 - a = 14.

This equation has two variables x and a. x^2 - a can be equal to 14 for infinite number of sets of x and a. It is not possible to determine a unique solution for a from the given equation.

As the equation x^2 - a = 14 has 2 independent variables it is not possible to determine a unique solution for a.

timw996's profile pic

Posted on (Answer #2)

Sorry there is another equation x^2 + a = 16

degeneratecircle's profile pic

Posted on (Answer #3)

I edited your original question in response to Answer #2.

If you subtract the first equation from the second one, you get `2a=2,` so `a=1.`

Althought it wasn't asked for, you can go further and solve for `x,` and we find that both `+-sqrt(15)` work. Finally, we can check our solution:

`(+-sqrt(15))^2-1=14` and `(+-sqrt(15))^2+1=16,` so it works.

atyourservice's profile pic

Posted on (Answer #4)


combine the problems:

x^2 -a - x^2 -a = 14 - 16


-2a = -2

divide by -2

a = 1

givingiswinning's profile pic

Posted on (Answer #5)

x^2 -a - x^2 -a = 14 - 16

-2a = -2

a = 1

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