# Write the slope-intercept form of the equation of the line passing through the point (3,6) and parallel to the line y= -4x + 3

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The slope of parallel lines is the same. For the line y = -4x + 3, which is in slope-intercept form, the slope is -4.

The line passing through the point (3, 6) should also have a slope of -4.

The equation of this line is given by (y - 6)/(x - 3) = -4

=> y - 6 = -4x + 12

=> y = -4x + 18

**The equation of the line passing through (3, 6) and parallel to the line y = -4x + 3 is y = -4x + 18 **

Slope-intercept form is y = mx + b

where: m=slope & b=y-intercept

The slope of the line // to y = -4x+3 is -4, if this line passes (3, 6) then

6 = -4(3) + b

b =18

again by slope-intercept form,

**y = -4x + 18**....eq. of // line to y =-4x+3

## y= -4x + 3

we can write above equation as 4x+y=3

Parallel line to the above line is 4x+y=k

but this line is passing (3,6).

so 4(3)+6=k

12+6=k

18 =k

So the parallel line is 4x+y=18 ,we can the line as y=-4x+18