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Your question is already in slope-intercept form. slope-intercept looks like this:
y = mx + b
which looks like yours with m = 1/2 and b = 1. If instead you are supposed to transform the equation into a different form, for example the point-intercept form, this is straightforward.
The point-intercept form takes this shape:
(y-y0) = m(x - x0)
This form is useful when you already know the slope, m, and a point P = (x0, y0) that the line passes through. In your case you know P = (-5, -4), and you know that m = 1/2.
y - -4 = 1/2(x - -5)
y + 4 = 1/2(x + 5) --> slope-intercept form.
You can verify that this is the same equation as y = 1/2x + 1 :
y = 1/2x + 5 - 4
y = 1/2x + 1
You are already in slope intercept form. Recall that the slope intercept form is
y = mx + b (where m is your slope, and by is the y-intercept)
I believe you're looking for a point slope form:
y - y1 = m(x - x1)
Which is fairly simple; just plug in!
y - (-4) = 1/2(x - (-5))
which simplifies to:
y + 4 = .5(x + 5)
The slope intercept is y=1/2x+1
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