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Write the ionic equation for the following reaction: Iron+copper(2) sulfate solution.
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You can only ask one question at a time so I edited down accordingly. We are asked to write the ionic equation for iron and copper (II) sulfate in aqueous solution. In an ionic equation, all dissolved ionic solids are written as the dissociated ions. The reactants can be written as follows:
Fe + CuSO4 -->
The iron in this reaction gets oxidized and the copper gets reduced. Two electrons are transferred from the iron to the copper. So the products are solid copper metal (Cu) and iron (II) sulfate (FeSO4). The iron sulfate is an ionic solid and will dissolve in water. So the chemical reaction is:
Fe + CuSO4 --> Cu + FeSO4
The ionic equation for the reaction is:
Fe (s) + Cu^2+ (aq) + SO4^2- (aq) --> Cu (s) + Fe^2+ (aq) + SO4^2- (aq)
The sulfate ion is called a spectator ion since it does not really participate in the chemical reaction. If we eliminate the spectator ions we will have the net ionic equation:
Fe (s) + Cu^2+ (aq) --> Cu (s) + Fe^2+ (aq)
You can use this same reasoning to figure out the other reaction as well.
Posted by ncchemist on March 24, 2013 at 12:09 AM (Answer #1)
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