Write the ionic equation for the displacement reaction, by adding the half equation. Magnesium+copper(2) sulfate--> magnesium sulfate+ copper

1 Answer | Add Yours

jeew-m's profile pic

jeew-m | College Teacher | (Level 1) Educator Emeritus

Posted on

In this reaction `Cu^(2+)` ions will be displaced by `Mg` and in the final solution we will get` Mg^(2+)` ions and `Cu` precipitate. `SO_4^(2-) ` ions in `CuSO_4` will be act as spectator ion which will not take part in the reaction.

`Mg_((s)) rarr Mg^(2+)_(aq)+2e ----(1)`

`Cu^(2+)_(aq)+2e rarr Cu_((s)) ----(2)`


(1)+(2) will give the answer.

`Mg_((s))+Cu^(2+)_(aq) rarrMg^(2+)_(aq)+Cu_((s))`

We’ve answered 317,539 questions. We can answer yours, too.

Ask a question