# write the function whose graph is the graph of` y=(x+3)^2` but is reflected about the x axis.

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Note that when a function y=f(x) is reflected about the x-axis, the new equation is y=-f(x). This means that when reflected about the x-axis, all original values of y are multiplied by -1. So we have,

`y=(x+3)^2`

Then, multiply right side by -1.

`y=-(x+3)^2`

*So, it's reflection about the x-axis is `y=-(x+3)^2` .*

Let's refer to the graph of `y=(x+3)^2` and it's reflection about the x-axis to verify.

The graph of `y=(x+3)^2 ` is the red curve. And the graph of `y=-(x+2)^2` is the blue curve. Both curves have the same x-coordinates. But the y-coordinates of the blue graph is the negative values of y of the other. So this proves that the blue curve is the reflection of the red curve about the x-axis.

**Hence, the reflection of `y=(x+3)^2` about the x-axis is `y=-(x+3)^2` .**

**Sources:**