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Write the equation of the line perpendicular to the line 2x +5y =12 and passing through...
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If y=mx+c is straight line and y=m'x+c is another straight line they will be perpendicular when m*m' = -1
2x+5y = 12
5y = 12-2x
y = (-2/5)x+(12/5)
Lets say the line perpendicular to this line is y = mx+c
So according to the above theorem;
(-2/5)*m = -1
m = 5/2
So we can write the perpendicular line as y = (5/2)x+c
Now it is given that this perpendicular line goes through point (-10,3).
3 = (5/2)*(-10)+c
c = 28
So the equation to the perpendicular line is y = (5/2)x+28
Posted by jeew-m on August 6, 2012 at 11:46 PM (Answer #1)
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