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Write the equation of the line passing through the point (-4,5) and perpendicular to...

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schooledmom | Salutatorian

Posted August 7, 2012 at 3:34 PM via web

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Write the equation of the line passing through the point (-4,5) and perpendicular to 3x-2y=12

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justaguide | College Teacher | (Level 2) Distinguished Educator

Posted August 7, 2012 at 3:46 PM (Answer #1)

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The equation of the line passing through the point (-4,5) and perpendicular to 3x-2y=12 has to be determined.

3x-2y=12

=> y = (3/2)x - 6

This is in the y = mx + c form where m is the slope. The product of the slope of two perpendicular lines is -1.

The slope of the required line is -2/3

As it passes thorugh (-4, 5)

(y - 5)/(x + 4) = -2/3

=> 3y - 15 = -2x - 8

=> 2x + 3y - 7 = 0

The equation of the required line is 2x + 3y - 7 = 0

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