Write the equation of a hyperbola with a center at (-5, -3), vertices at (-5, -5) and (-5, -1) and co-vertices at (-11, -3) and (1, -3)

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Lenth of of transverse axis=`sqrt((-5+5)^2+(-5+1)^2)=sqrt(16)`


so semi transverse axis=2

Length of conjugate axis=`sqrt((-11-1)^2+(-3+3)^2)=sqrt(144)`


So semi conjugate axis=6

Thus equation of the hyperbola



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