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Write down the general form of a monic quadratic whos axis of symmetry is x=-2.
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The general form of monic quadratic equation is
`x^2+bx+c=0` i.e. leading coefficient is 1.
The general form of a monic quadratic equation whose axis of symmetry is x=-2.
`(x+2)^2-c=0` , c is non negative constant.
for other parts please repost your proble.
Posted by pramodpandey on May 26, 2013 at 6:48 AM (Answer #1)
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Hence find the equation of such quadratic:
a) passing through the origin, b) passing through (5,1) c) with x = 1 as one zero, d) with y intercept -6 e) touching the line y = -2 f) with range y≥7 g) whos tangent at x = 1 passes thorugh (0,0) h) which is tangent to y=-x^2
Posted by lazaa on May 26, 2013 at 7:17 AM (Reply #1)
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