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Write a dissociation equation for the compound sodium carbonate. Determine the...
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In aqueous solution, sodium carbonate dissociates as:
`Na_2CO_3 (s) stackrel(rarr)(larr)2Na^+(aq.) +CO_3^(2-)(aq.)`
From the ratio of different species it is evdent that, one molecule of sodium carbonate dissociates to produce two ions of `Na^+` and one ion of `CO_3^(2-)` .
Therefore, taking a 0.100 M solution of sodium carbonate, the concentration of `Na^+(aq.)` ions would be 2*0.100, i.e. 0.200M and concentration of `CO_3^(2-)(aq.)` ions would be 0.100M.
Posted by llltkl on September 2, 2013 at 6:53 AM (Answer #1)
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