Write a dissociation equation for the compound sodium carbonate. Determine the concentration of each ion in a 0.100 M solution.
1 Answer | Add Yours
In aqueous solution, sodium carbonate dissociates as:
`Na_2CO_3 (s) stackrel(rarr)(larr)2Na^+(aq.) +CO_3^(2-)(aq.)`
From the ratio of different species it is evdent that, one molecule of sodium carbonate dissociates to produce two ions of `Na^+` and one ion of `CO_3^(2-)` .
Therefore, taking a 0.100 M solution of sodium carbonate, the concentration of `Na^+(aq.)` ions would be 2*0.100, i.e. 0.200M and concentration of `CO_3^(2-)(aq.)` ions would be 0.100M.
Join to answer this question
Join a community of thousands of dedicated teachers and students.Join eNotes