Write an equation that gives the height (in feet) of the football as a function of the time (in seconds) since it was punted

A kicker punts a football from 3 feet above the ground with an initial velocity of 47 feet per second.

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Given the assumptions of no friction and constant acceleration of 32 feet per second per second, the height of an object is given by

`h=-1/2g t^2+v_0t+h_0` where `g=32` , `v_0=47` is the initial speed and `h_0=3` is the initial height of the ball. Sub in these values to get:

`h=-16t^2+47t+3`

**The height of the ball in feet after t seconds is `h=-16t^2+47t+3` .**

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