Write an equation of the line that passes through the point (-1,3) and is parallel to the line y=2x+1. ``
I keep getting 2x-1/3 but my teacher said that was wrong.
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The equation of a line that is parallel to `y = 2x + 1` must have the same slope. Since `y=2x + 1` is written in slope-intercept form `(y=mx+b)` the slope (m) is 2.
To pass through the point (-1,3) we can use the point slope form for the equation of the line.
Point-slope form: `y - y_(1)= m(x - x_1)`
This gives us the equation: `y - 3 = 2(x - (-1))`
`y - 3 = 2(x+1)`
`y - 3 = 2x + 2`
`y = 2x + 5`
The solution is y = 2x + 5.
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