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Evaluate `log_8 16 + log_8 32 - 7*log_8 2`

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donatchange | Student, Grade 11 | eNoter

Posted April 1, 2012 at 11:21 PM via web

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Evaluate `log_8 16 + log_8 32 - 7*log_8 2`

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justaguide | College Teacher | (Level 2) Distinguished Educator

Posted April 1, 2012 at 11:27 PM (Answer #1)

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The value of `log_8 16 + log_8 32 - 7*log_8 2` has to be determined.

`log_8 16 + log_8 32 - 7*log_8 2`

=> `log_8 ((16*32)/2^7)`

=> `log_8 ((2^4*2^5)/2^7)`

=> `log_8 (2^2)`

=> `(log_2 4)/(log_2 8)`

=> `2/3`

The value of `log_8 16 + log_8 32 - 7*log_8 2` = `2/3`

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