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When you evaluate any log(base a) b where a > b, a does not equal 1, then: a)...
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The value of `log_a b` has to be evaluated when a > b and a does not equal 1.
If `X = log_a b` , `b = X^a`
Maintaining a > b:
If a > 1 and b > 1, `log_a b` < 1
If a `!=` 1, b = 1, `log_a b` = 0
If a < 1 and b < 1, `log_a b` > 1
The correct answer is option D. Given that a > b and a `!=` 1, it is not possible to determine the value of `log_a b`
Posted by justaguide on August 17, 2013 at 6:58 AM (Answer #2)
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