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When you evaluate any log (base a) b where a > b and b> 1 then: a) log (base a)...
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The value of `log_a b` has to be determined given that a > b and b > 1.
Expressing `log_a b` in terms of logarithms with the same base:
`log_a b = (log b)/(log a)`
As a > b > 1, log a > log b, and log a and log b are positive.
The value of `log_a b` lies between 0 and 1.
The correct answer is b.
Posted by justaguide on August 27, 2013 at 5:59 PM (Answer #1)
High School Teacher
since b>1 and a>b
ln is an increasing fuction in `(1,oo)`
`ln(a)>0 ad ln(b)>0`
THus correct answer is B
Posted by aruv on August 27, 2013 at 7:20 PM (Answer #2)
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