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When sodium carbonate reacts with hydrochloric acid, the carbonic acid that is formed...

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t521863 | Student, Grade 10 | Valedictorian

Posted September 1, 2013 at 11:57 PM via web

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When sodium carbonate reacts with hydrochloric acid, the carbonic acid that is formed immediately breaks down into carbon dioxide and water. What mass of sodium carbonate would have been originally present if 5.0 L of carbon dioxide was produced? NA2CO3--> 2NaCL + CO2+H2O

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llltkl | College Teacher | Valedictorian

Posted September 2, 2013 at 7:18 AM (Answer #1)

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When sodium carbonate reacts with hydrochloric acid, the carbonic acid that is formed immediately breaks down into carbon dioxide and water. What mass of sodium carbonate would have been originally present if 5.0 L of carbon dioxide was produced?

The balanced chemical equation for the reaction of sodium carbonate  and hydrochloric acid is:

`Na_2CO_3 +2HCl = 2NaCl + CO_2 (g)+H_2O`

From the stoichiometry of this reaction, it follows that:

At NTP, 1 gram-mole, i.e. 22.4 litre `CO_2 (g)` is produced from (2*23+12+3*16), i.e. 106 g `Na_2CO_3` .

Therefore 5.0 L `CO_2` (g) will be produced from `(106*5.0)/22.4=23.66` g `Na_2CO_3`

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