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To solve apply the angular displacement formula which is:
d - linear displacement
r - radius of the curvature, and
`theta` - angular displacement in radians
But, before substituting the values to the formula, convert the given degrees to radians.
`150 ^o xx (pirad)/(180^o)=(5pi)/6` `rad`
Then, plug-in r=1.4 feet and `theta =(5pi)/6` radians to the formula.
Hence, the distance travelled by the bike is 3.67 feet.
I wheels rotate `2 pi` then the distance is `2pi r` r radius.
Since travel only `150^0 = 5/6 pi` then the travel is of `t=5/6 pi d=`
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