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What's a factor of x^3 - x - 6 =0
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High School Teacher
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We will substitute with x= 2.
==> x^3 - x - 6 = 0
==> 8 - 2 -6 = 0
Then x= 2 is a root for the equation.
==> (x-2) is a factor.
Now we will divide by (x-2) to find other factors.
==> (x^3 - x - 6) = (x-2) (x^2 + 2x+ 3)
Now sine delta = (4-4*3) = 4-12 = -8 < 0
Then there are no Real roots foe the quadratic equation.
Then the factors of the equation are : (x-2) and (x^2 + 2x+3)
Posted by hala718 on May 20, 2011 at 10:01 PM (Answer #1)
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