What is the 29th term of the sequence : -121, -108,-95,-82

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The 29th term of the series beginning with -121, -108, -95, -82 has to be determined.

-108 + 121 = 13

-95 + 108 = 13

-82 + 95 = 13

The first term of the series is -121 and the common difference is 13. This forms an arithmetic series.

The nth term of an arithmetic series with 1st term a and common difference d is `t_n = a + (n - 1)*d`

For the given series `T_29 = -121 + 13*(29 - 1) = 243`

**The 29th term of the given series is 243**

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