What are x and y? y/1+i = x^2 + 4/x+2i

1 Answer | Add Yours

Top Answer

aruv's profile pic

Posted on





Comparing real and imaginary parts



Thus we have



Solving above biquadratic equation, we have two real roots and other two roots are complex. Since x can not be complex so ignore them. Real roots are

`x approx.93`


So `yapprox 3.29`  when `x approx .93`  and

`yapprox2.56` when `xapprox-1.50` 

We’ve answered 330,436 questions. We can answer yours, too.

Ask a question