# what is x,y from the equation.3x-ix-2y=12-iy-iPlease help

### 2 Answers | Add Yours

We need to find x and y from 3x - ix - 2y = 12 - iy - i

3x - ix - 2y = 12 - iy - i

=> 3x - 2y - ix = 12 - i(y + 1)

equate the real and the complex coefficients.

3x - 2y = 12

x = y + 1

substitute in 3x - 2y = 12

=> 3(y + 1) - 2y = 12

=> 3y + 3 - 2y = 12

=> y = 9

x = y + 1

=> x = 10

**The required values are x = 10 and y = 9.**

Well we have to figure out how much is x and y fro the equation 3x-ix-2y=12-iy-i. First lets make a small grouping of these elements we know and those we dont know,and keep in mind you have some complesx number,try to make it in a formof this a+bi We have;

(3x-2y)+(x-y)i=12-i Now simply add this as a system,by using the Substitution Method you have.

3x-2y=12

x=-y-1

where **y=-3 and x=2**

** **