What volume will 32g of oxygen at 25˚C and 100KPa occupy

### 1 Answer | Add Yours

Using ideal gas law;

`PV = nRT`

`V = (nRT)/P`

`P = 100Kpa = 100xx0.009869atm = 0.9869atm`

`n = (32g)/(32g/(mol)) = 1 mol`

`R = 0.08206 L·atm·mol^(-1)·K^(-1)`

`T = 25C = 25+273 K = 298K`

`V = (nRT)/P`

`V = (1xx0.08206xx298)/(0.9869)`

`V = 24.7784L`

*So the volume of `O_2` gas would be 24.7784L*

*Assumption*

*`O_2` act as a ideal gas.*

**Sources:**

### Join to answer this question

Join a community of thousands of dedicated teachers and students.

Join eNotes