# For what values of a does y = ax2 - 8x +4 have no x-intercepts?answer and explanation please

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The graph of the given equation will intercept x when y = 0

Simply speaking if `ax^2 - 8x +4 = 0` has no solutions then the x-axis would not be intercept.

For `ax^2 - 8x +4 = 0` not to have solutions then

`Delta` <0

`Delta ` = (-8)^2-4*a*4 = 64-16a

For non-solutions;

`Delta` <0

64-16a <0

64 < 16a

4 < a

**So `y = ax^2 - 8x +4` does not have x-intercept if a>4.**