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What are the values of c? The follwing system is an augmented matrix that has no...
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The augmented matrix has no trivial solution. ie.
1 c-1 1
D= 0 c 4
1 c c+1
By elementry row operation
1 c-1 1
D = 0 c 4
0 1 1
If we expand this then det (d)=C^2-4
for non trivial solution we have Det(D)=0
Posted by pramodpandey on March 17, 2013 at 12:45 PM (Answer #3)
High School Teacher
If the augmented matrix has no trivial solution then we cannot find the value of c in the real field. As it is coming c^2+4=0 i.e. c=+-(2i).
If we prepare the augmented matrix and reduce by elementary operations we get 4-c^2=0 or c=+2 and c=-2.
For above values of c, the system has no trivial solutions. As we are getting a 2by2 matrix for three variables.
Posted by rakesh05 on March 17, 2013 at 9:45 AM (Answer #1)
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