What value should be added to each side of x^2+4x=-6 to complete the square?
Would it be -4 that needs to be added to each side?
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For x^2+4x=-6, the square on the left needs to be completed.
Use the relation (a+b)^2 = a^2 + b^2 + 2*a*b
=> x^2 + 2*2*x = -6
=> x^2 + 2*2*x + 2^2 = -6 + 2^2
=> (x + 2)^2 = -6 +4
=> (x + 2)^2 = -2
The number 4 has to be added to both the sides to complete the square on the left.
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