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What value should be added to each side of x^2+4x=-6 to complete the square? Would it...

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What value should be added to each side of x^2+4x=-6 to complete the square?

Would it be -4 that needs to be added to each side?

Thanks much,

Tricia

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Posted (Answer #1)

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For x^2+4x=-6, the square on the left needs to be completed.

Use the relation (a+b)^2 = a^2 + b^2 + 2*a*b

x^2+4x=-6

=> x^2 + 2*2*x = -6

=> x^2 + 2*2*x + 2^2 = -6 + 2^2

=> (x + 2)^2 = -6 +4

=> (x + 2)^2 = -2

The number 4 has to be added to both the sides to complete the square on the left.

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