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For what value of a is the remainder -3 when x^3–ax^2+5 is divided by (x-2)?Show step...
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If you divide `x^3-ax^2+5` by `(x-2)` , you would get.
`(x^3-ax^2+5)/(x-2) = x^2+(2-a)x+2(2-a)+ (5+4(2-a))/(x-2)`
The remainder is `5+4(2-a).`
For `a= 4` , the remainder of `(x^3-ax^2+5)/(x-2)` is -3.
Posted by thilina-g on May 17, 2012 at 7:53 AM (Answer #1)
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