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For what value of a is the remainder -3 when x^3–ax^2+5 is divided by (x-2)?Show step...

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spock4 | Student, Undergraduate | (Level 1) Honors

Posted May 17, 2012 at 6:48 AM via web

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For what value of a is the remainder -3 when x^3–ax^2+5 is divided by (x-2)?

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thilina-g | College Teacher | (Level 1) Educator

Posted May 17, 2012 at 7:53 AM (Answer #1)

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If you divide `x^3-ax^2+5` by `(x-2)` , you would get.

`(x^3-ax^2+5)/(x-2) = x^2+(2-a)x+2(2-a)+ (5+4(2-a))/(x-2)`

The remainder is `5+4(2-a).`

Therefore,

`5+4(2-a) =-3`

`4(2-a) =-8`

`2-a =-2`

`a =4`

 

For `a= 4` , the remainder of `(x^3-ax^2+5)/(x-2)` is -3.

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