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what is the value of p(x)=xsquare-3x-4 at x=2
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Supposing that you need to find the value of `p(x) = x^2 - 3x - 4` at x=2, you need to substitute 2 for x in equation `p(x) = x^2 - 3x - 4` such that:
`p(2) = 2^2 - 3*2 - 4`
`p(2) = 4 - 6 - 4`
Reducing like terms yields:
`p(2) = -6`
Hence, evaluating the value of `p(x) = x^2 - 3x - 4` at x=2 yields `p(2) = -6` .
Posted by sciencesolve on July 4, 2012 at 4:55 PM (Answer #1)
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